Expand and simplify: \( \begin{array}{ll}\text { (a) } 2 x(3 x-4 y)-\left(7 x^{2}-2 x y\right) & \text { (b) } \\ \text { (c) } r^{10} & (5 y+1)^{2}-(3 y+4)(2-3 y) \\ \text { (d) }(8 m-y)^{2}-(3 x-2 y)^{2}+(x-4 y)(x+4 y) \\ \text { (c) } x^{6}+\left(x^{3}-3 y\right)\left(x^{3}+3 y\right) & \text { (f) }\end{array} \)
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Let's tackle both parts step by step! 1. For part (a), \( 2x(3x - 4y) - (7x^2 - 2xy) \): Expand \( 2x(3x - 4y) = 6x^2 - 8xy \). Thus, we have: \[ 6x^2 - 8xy - 7x^2 + 2xy = (6x^2 - 7x^2) + (-8xy + 2xy) = -x^2 - 6xy. \] 2. For part (c), \( (5y + 1)^2 - (3y + 4)(2 - 3y) \): Start by expanding \( (5y + 1)^2 = 25y^2 + 10y + 1 \). The second term becomes: \[ (3y + 4)(2 - 3y) = 6y - 9y^2 + 8 - 12y = -9y^2 - 6y + 8. \] Now substitute and simplify: \[ 25y^2 + 10y + 1 - (-9y^2 - 6y + 8) = 25y^2 + 10y + 1 + 9y^2 + 6y - 8 = 34y^2 + 16y - 7. \] So, the simplified results are: - (a) \(-x^2 - 6xy\) - (c) \(34y^2 + 16y - 7\)