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A line passes through the point \( (-4,-7) \) and has a slope of \( -\frac{5}{4} \). Write an equation in slope-intercept form for this line.

Ask by Parry Grant. in the United States
Feb 03,2025

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Tutor-Verified Answer

Answer

The equation of the line in slope-intercept form is \( y = -\frac{5}{4}x - 12 \).

Solution

To find the equation of a line in **slope-intercept form**, which is: \[ y = mx + b \] where: - \( m \) is the slope of the line - \( b \) is the y-intercept (the point where the line crosses the y-axis) **Given:** - Slope (\( m \)) = \( -\frac{5}{4} \) - A point on the line = \( (-4, -7) \) **Steps to Find the Equation:** 1. **Plug the known values into the slope-intercept form.** We know \( m = -\frac{5}{4} \) and the line passes through \( (-4, -7) \), so: \[ -7 = \left(-\frac{5}{4}\right)(-4) + b \] 2. **Solve for \( b \) (the y-intercept).** \[ -7 = \left(-\frac{5}{4}\right) \times (-4) + b \] \[ -7 = 5 + b \] \[ b = -7 - 5 \] \[ b = -12 \] 3. **Write the final equation with the slope and y-intercept.** \[ y = -\frac{5}{4}x - 12 \] **Final Answer:** \[ \boxed{y = -\dfrac{5}{4}\,x\ -\ 12} \]

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To find the equation of a line in slope-intercept form \( y = mx + b \), we start with the slope \( m = -\frac{5}{4} \) and the point \( (-4, -7) \). We can use the point-slope form of the equation first, which is given by \( y - y_1 = m(x - x_1) \). Substituting in the values, we have: \[ y - (-7) = -\frac{5}{4}(x - (-4)) \] This simplifies to: \[ y + 7 = -\frac{5}{4}(x + 4) \] Now, distribute the slope: \[ y + 7 = -\frac{5}{4}x - 5 \] Next, isolate \( y \) by subtracting 7 from both sides: \[ y = -\frac{5}{4}x - 5 - 7 \] Finally, combine the constant terms: \[ y = -\frac{5}{4}x - 12 \] So, the equation of the line in slope-intercept form is: \[ y = -\frac{5}{4}x - 12 \]

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