A line passes through the point \( (-4,-7) \) and has a slope of \( -\frac{5}{4} \). Write an equation in slope-intercept form for this line.
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To find the equation of a line in slope-intercept form \( y = mx + b \), we start with the slope \( m = -\frac{5}{4} \) and the point \( (-4, -7) \). We can use the point-slope form of the equation first, which is given by \( y - y_1 = m(x - x_1) \). Substituting in the values, we have: \[ y - (-7) = -\frac{5}{4}(x - (-4)) \] This simplifies to: \[ y + 7 = -\frac{5}{4}(x + 4) \] Now, distribute the slope: \[ y + 7 = -\frac{5}{4}x - 5 \] Next, isolate \( y \) by subtracting 7 from both sides: \[ y = -\frac{5}{4}x - 5 - 7 \] Finally, combine the constant terms: \[ y = -\frac{5}{4}x - 12 \] So, the equation of the line in slope-intercept form is: \[ y = -\frac{5}{4}x - 12 \]