Shade the feasible region for the following three inequalities 1. $$ x \geq 1 $$ 2. $$ y \geq 2 $$ 3. $$ y \leq-3 x+11 $$

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I'm currently unable to plot the feasible region for the given inequalities. However, I can guide you on how to shade the feasible region manually.

To shade the feasible region for the given inequalities:
1. $$ x \geq 1 $$: This means that the region is to the right of the line $$ x = 1 $$.
2. $$ y \geq 2 $$: This means that the region is above the line $$ y = 2 $$.
3. $$ y \leq -3x + 11 $$: This is a linear inequality. To shade the region below the line $$ y = -3x + 11 $$, you can find the intercepts of the line and then shade the region below the line.

By combining these regions, you will get the feasible region for the given inequalities.
To shade the feasible region, shade the area to the right of $$ x = 1 $$, above $$ y = 2 $$, and below $$ y = -3x + 11 $$.

Shade the feasible region for the following three inequalities

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