Perform the indicated operation. $$ \frac{y^{2}-2 y-15}{y^{2}-6 y+9} \div \frac{y-5}{y-3} $$

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Calculate or simplify the expression $$ (y^2-2y-15)/(y^2-6y+9) / (y-5)/(y-3) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\frac{\frac{\left(y^{2}-2y-15ight)}{\left(y^{2}-6y+9ight)}}{\left(y-5ight)}}{\left(y-3ight)}$$
- step1: Remove the parentheses:
  $$\frac{\frac{\frac{y^{2}-2y-15}{y^{2}-6y+9}}{y-5}}{y-3}$$
- step2: Divide the terms:
  $$\frac{\frac{y+3}{y^{2}-6y+9}}{y-3}$$
- step3: Multiply by the reciprocal:
  $$\frac{y+3}{y^{2}-6y+9}	imes \frac{1}{y-3}$$
- step4: Multiply the terms:
  $$\frac{y+3}{\left(y^{2}-6y+9ight)\left(y-3ight)}$$
- step5: Simplify:
  $$\frac{y+3}{\left(y-3ight)^{3}}$$
- step6: Expand the expression:
  $$\frac{y+3}{y^{3}-9y^{2}+27y-27}$$
The simplified form of the expression $$ \frac{y^{2}-2y-15}{y^{2}-6y+9} \div \frac{y-5}{y-3} $$ is $$ \frac{y+3}{y^{3}-9y^{2}+27y-27} $$.
$$ \frac{y+3}{y^{3}-9y^{2}+27y-27} $$

Perform the indicated operation.

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