Question
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Multiply the rational expressions. \( \frac{32 w^{5}}{27} \cdot \frac{3}{2 w^{7}}=\square \)

Ask by Cummings O'Quinn. in the United States
Jan 27,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\[ \frac{16}{9w^{2}} \]

Solution

To multiply the rational expressions: \[ \frac{32 w^{5}}{27} \cdot \frac{3}{2 w^{7}} \] **Step 1: Multiply the coefficients and the variables separately.** - **Coefficients:** \[ \frac{32}{27} \times \frac{3}{2} = \frac{32 \times 3}{27 \times 2} = \frac{96}{54} \] Simplify \(\frac{96}{54}\) by dividing both the numerator and the denominator by 6: \[ \frac{96 \div 6}{54 \div 6} = \frac{16}{9} \] - **Variables:** \[ w^{5} \times \frac{1}{w^{7}} = \frac{w^{5}}{w^{7}} = w^{5-7} = w^{-2} = \frac{1}{w^2} \] **Step 2: Combine the simplified coefficients and variables.** \[ \frac{16}{9} \times \frac{1}{w^2} = \frac{16}{9 w^2} \] **Final Answer:** \[ \frac{16}{9 w^{2}} \]

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Mind Expander

To multiply the rational expressions, you simply multiply the numerators together and the denominators together. Starting with the numerators: \(32 w^{5} \cdot 3 = 96 w^{5}\). Now for the denominators: \(27 \cdot 2 w^{7} = 54 w^{7}\). Putting it all together, you get: \[ \frac{96 w^{5}}{54 w^{7}} \] Next, simplify the expression. You can reduce \(96\) and \(54\) (both divisible by \(6\)): \[ \frac{16 w^{5}}{9 w^{7}} \] Since \(w^{5}\) in the numerator and \(w^{7}\) in the denominator can be simplified, you subtract the powers: \[ \frac{16}{9 w^{2}} \] So, the final answer is: \[ \frac{16}{9 w^{2}}. \]

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