Use your result from the previous task to find the sum. \( 6 a b^{2} \) \( 3 a b+3 b^{2} \) \( -6 a^{2}+3 a b+3 b^{2} \) \( -6 a^{2}-13 a b+3 b^{2} \) DONE

To find the sum of the four expressions given, we will simply combine like terms systematically. Start with: 1. \( 6ab^2 \) 2. \( 3ab + 3b^2 \) 3. \( -6a^2 + 3ab + 3b^2 \) 4. \( -6a^2 - 13ab + 3b^2 \) Collecting all the terms, we have: - **For \(a^2\)**: \( -6a^2 - 6a^2 = -12a^2 \) - **For \(ab\)**: \( 6ab^2 + 3ab + 3ab - 13ab = 6ab^2 - 7ab \) - **For \(b^2\)**: \( 6ab^2 + 3b^2 + 3b^2 = 12b^2 \) Combining these, we get the sum: \[ -12a^2 - 7ab + 12b^2 \]