\( \begin{array}{ll}\text { 9) }-38=7-9 \cdot x & x=\square \\ \text { 10| }-78=-40-2 \cdot x & x=\square \\ \text { 11) }-30=-62+2 \cdot x & x=\square \\ \text { 12 } 17=-13+5 \cdot x & x=\square\end{array} \)

To solve these equations for \( x \): For the first equation: \(-38 = 7 - 9 \cdot x\) First, subtract 7 from both sides: \(-45 = -9 \cdot x\) Now, divide by -9: \(x = 5\) For the second equation: \(-78 = -40 - 2 \cdot x\) Add 40 to both sides: \(-38 = -2 \cdot x\) Divide by -2: \(x = 19\) For the third equation: \(-30 = -62 + 2 \cdot x\) Add 62 to both sides: \(32 = 2 \cdot x\) Divide by 2: \(x = 16\) For the fourth equation: \(17 = -13 + 5 \cdot x\) Add 13 to both sides: \(30 = 5 \cdot x\) Divide by 5: \(x = 6\) So, the solutions are: 9) \(x = 5\) 10) \(x = 19\) 11) \(x = 16\) 12) \(x = 6\)