The length of square $$ A $$ is twice the length of the side of square $$ B $$. What is the ratio between the area of square $$ A $$ and square $$ B $$ ?

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To determine the ratio between the areas of square $$ A $$ and square $$ B $$, let's follow these steps:

1. **Define the Side Lengths:**
   - Let the side length of square $$ B $$ be $$ s $$.
   - According to the problem, the side length of square $$ A $$ is twice that of square $$ B $$. Therefore, the side length of square $$ A $$ is $$ 2s $$.

2. **Calculate the Areas:**
   - **Area of Square $$ B $$:**
     $$
     \text{Area}_B = s \times s = s^2
     $$
   - **Area of Square $$ A $$:**
     $$
     \text{Area}_A = (2s) \times (2s) = 4s^2
     $$

3. **Determine the Ratio of Areas:**
   - The ratio of the area of square $$ A $$ to the area of square $$ B $$ is:
     $$
     \frac{\text{Area}_A}{\text{Area}_B} = \frac{4s^2}{s^2} = 4
     $$
   - This simplifies to a ratio of $$ 4:1 $$.

**Conclusion:**
The area of square $$ A $$ is **4 to 1** compared to the area of square $$ B $$.
The area of square $$ A $$ is 4 times the area of square $$ B $$, so the ratio is 4:1.

The length of square is twice the length of the side of square . What is the ratio between the area of square and square ?

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