A group of friends wants to go to the amusement park. They have no more than \( \$ 125 \) to spend on parking and admission. Parking is \( \$ 16.75 \), and tickets cost \( \$ 20.25 \) per person, including tax. Which inequality can be used to determine \( x \), the maximum number of people who can go to the amusement park? Answer \( \begin{array}{lll}16.75+20.25 x \geq 125 & \text { (O) } 16.75+20.25(x+16.75) \geq 125 & \text { Submil Answer } \\ 20.25(x+16.75) \leq 125 & \end{array} \)

To determine the maximum number of people \( x \) that can go to the amusement park without exceeding a total budget of \$125, we need to account for both parking and admission costs. **Given:** - **Parking cost:** \$16.75 (a fixed cost) - **Admission cost per person:** \$20.25 - **Total budget:** \$125 **Setting Up the Inequality:** 1. **Total Cost:** The total cost consists of the fixed parking fee plus the admission cost for each person. This can be expressed as: \[ \text{Total Cost} = 16.75 + 20.25x \] 2. **Budget Constraint:** The total cost should not exceed \$125: \[ 16.75 + 20.25x \leq 125 \] **Final Inequality:** \[ 16.75 + 20.25x \leq 125 \] This inequality correctly represents the maximum number of people \( x \) that can attend the amusement park without surpassing the \$125 budget. **Answer:** \[ 16.75 + 20.25\,x \leq 125 \]