Question
Rewrite the following polynomial in standard form. \[ -\frac{x^{2}}{10}+10-x^{3} \] Answer Attempt 1 out of 2
Ask by Montgomery Mcfarlane. in the United States
Feb 03,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\[
- x^{3} - \frac{1}{10}x^{2} + 10
\]
Solution
To rewrite the polynomial \(-\frac{x^{2}}{10} + 10 - x^{3}\) in standard form, arrange the terms in descending order of the exponents of \(x\).
**Standard Form:**
\[
- x^{3} - \frac{1}{10}x^{2} + 10
\]
**Explanation:**
1. **Identify the terms and their degrees:**
- \(-x^3\) has degree 3.
- \(-\frac{1}{10}x^2\) has degree 2.
- \(+10\) is the constant term with degree 0.
2. **Arrange the terms from highest to lowest degree:**
- Start with \(-x^3\).
- Next, add \(-\frac{1}{10}x^2\).
- Finally, include the constant term \(+10\).
So, the polynomial in standard form is:
\[
- x^{3} - \frac{1}{10}x^{2} + 10
\]
Reviewed and approved by the UpStudy tutoring team
Like
error msg
Explain
Simplify this solution
Mind Expander
To rewrite the polynomial \(-\frac{x^{2}}{10}+10-x^{3}\) in standard form, we need to arrange the terms in descending order based on the degree of \(x\). The term with the highest degree is \(-x^{3}\), followed by the \(-\frac{x^{2}}{10}\), and finally the constant term \(10\). So, the polynomial in standard form is: \[-x^{3} - \frac{x^{2}}{10} + 10\]