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Rewrite the following polynomial in standard form. \[ -\frac{x^{2}}{10}+10-x^{3} \] Answer Attempt 1 out of 2

Ask by Montgomery Mcfarlane. in the United States
Feb 03,2025

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Answer

\[ - x^{3} - \frac{1}{10}x^{2} + 10 \]

Solution

To rewrite the polynomial \(-\frac{x^{2}}{10} + 10 - x^{3}\) in standard form, arrange the terms in descending order of the exponents of \(x\). **Standard Form:** \[ - x^{3} - \frac{1}{10}x^{2} + 10 \] **Explanation:** 1. **Identify the terms and their degrees:** - \(-x^3\) has degree 3. - \(-\frac{1}{10}x^2\) has degree 2. - \(+10\) is the constant term with degree 0. 2. **Arrange the terms from highest to lowest degree:** - Start with \(-x^3\). - Next, add \(-\frac{1}{10}x^2\). - Finally, include the constant term \(+10\). So, the polynomial in standard form is: \[ - x^{3} - \frac{1}{10}x^{2} + 10 \]

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To rewrite the polynomial \(-\frac{x^{2}}{10}+10-x^{3}\) in standard form, we need to arrange the terms in descending order based on the degree of \(x\). The term with the highest degree is \(-x^{3}\), followed by the \(-\frac{x^{2}}{10}\), and finally the constant term \(10\). So, the polynomial in standard form is: \[-x^{3} - \frac{x^{2}}{10} + 10\]

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