d. 9 is a multiple of 45 . For each number, (a) list all its factors in ascending order and (b) list its first 6 multiples. 2. 12

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To solve this study problem, we need to find the factors of 9 and its first 6 multiples, and then do the same for 12.

Let's start with 9:

a) List all factors of 9 in ascending order:
To find the factors of 9, we need to find all the numbers that divide 9 without leaving a remainder. The factors of 9 are:

1 (because 9 ÷ 1 = 9)
3 (because 9 ÷ 3 = 3)
9 (because 9 ÷ 9 = 1)

So, the factors of 9 in ascending order are: 1, 3, 9.

b) List the first 6 multiples of 9:
To find the multiples of 9, we multiply 9 by the first 6 positive integers:

1 × 9 = 9
2 × 9 = 18
3 × 9 = 27
4 × 9 = 36
5 × 9 = 45
6 × 9 = 54

So, the first 6 multiples of 9 are: 9, 18, 27, 36, 45, 54.

Now let's move on to 12:

a) List all factors of 12 in ascending order:
To find the factors of 12, we need to find all the numbers that divide 12 without leaving a remainder. The factors of 12 are:

1 (because 12 ÷ 1 = 12)
2 (because 12 ÷ 2 = 6)
3 (because 12 ÷ 3 = 4)
4 (because 12 ÷ 4 = 3)
6 (because 12 ÷ 6 = 2)
12 (because 12 ÷ 12 = 1)

So, the factors of 12 in ascending order are: 1, 2, 3, 4, 6, 12.

b) List the first 6 multiples of 12:
To find the multiples of 12, we multiply 12 by the first 6 positive integers:

1 × 12 = 12
2 × 12 = 24
3 × 12 = 36
4 × 12 = 48
5 × 12 = 60
6 × 12 = 72

So, the first 6 multiples of 12 are: 12, 24, 36, 48, 60, 72.

In summary:

For 9:
- Factors: 1, 3, 9
- First 6 multiples: 9, 18, 27, 36, 45, 54

For 12:
- Factors: 1, 2, 3, 4, 6, 12
- First 6 multiples: 12, 24, 36, 48, 60, 72
For 9: Factors - 1, 3, 9; Multiples - 9, 18, 27, 36, 45, 54 For 12: Factors - 1, 2, 3, 4, 6, 12; Multiples - 12, 24, 36, 48, 60, 72

d. 9 is a multiple of 45 . For each number, (a) list all its factors in ascending order and (b) list its first 6 multiples. 2. 12

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