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Two variables are defined, a regression equation is given, and one data point is given. \[ \begin{array}{l} \text { Weight = maximum weight capable of bench pressing (pounds) } \\ \text { Training }=\text { number of hours spent lifting weights a week } \\ \text { Weight }=96+11.6 \text { (Training) } \end{array} \] The data point is an individual who trains 5 hours a week and can bench 150 pounds. 3) Find the predicted value for the data point and compute the residual. inter the exact answers. redicted value = \( \square \) lbs tesidual = \( \square \) lbs

Ask by Donnelly Morrison. in the United States
Feb 03,2025

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Answer

Predicted value = 154 lbs Residual = -4 lbs

Solution

To solve the problem, we'll use the given regression equation and the data point provided. **Regression Equation:** \[ \text{Weight} = 96 + 11.6 \times \text{Training} \] **Given Data Point:** - Training = 5 hours per week - Actual Weight = 150 pounds **1. Calculate the Predicted Value:** Substitute the value of Training into the regression equation: \[ \text{Predicted Weight} = 96 + 11.6 \times 5 = 96 + 58 = 154 \text{ pounds} \] **2. Compute the Residual:** Residual is the difference between the actual weight and the predicted weight: \[ \text{Residual} = \text{Actual Weight} - \text{Predicted Weight} = 150 - 154 = -4 \text{ pounds} \] **Final Answers:** - **Predicted value =** \( 154 \) lbs - **Residual =** \( -4 \) lbs

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To find the predicted value using the given regression equation, we plug in the hours of training. Using the equation \( \text{Weight} = 96 + 11.6 \times \text{Training} \): For \( \text{Training} = 5 \) hours: \[ \text{Weight} = 96 + 11.6 \times 5 = 96 + 58 = 154 \text{ lbs} \] Now, we compute the residual, which is the difference between the observed value and the predicted value. The observed value is 150 lbs: \[ \text{Residual} = \text{Observed Weight} - \text{Predicted Weight} = 150 - 154 = -4 \text{ lbs} \] Thus, the answers are: Predicted value = \( 154 \) lbs Residual = \( -4 \) lbs

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