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A bleach is \( 5.25 \% \) sodium hypochlorite and swimming pool shock treatment is \( 10.5 \% \) sodium hypochlorite. How much of each item must be mixed to get 6 cups of a mixture that is \( 7.3 \% \) sodium hypochlorito? To get 6 cups of a mixture that is \( 7.3 \% \) sodium hypochlorite, approximately \( \square \) cups of a bleach and approximately \( \square \) cups of a swimming pool shock treatment must be mixed. (Round to two decimal places as needed.)

Ask by Patel Lyons. in the United States
Feb 04,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

To make 6 cups of a 7.3% sodium hypochlorite mixture, mix approximately 3.66 cups of bleach with 2.34 cups of swimming pool shock treatment.

Solution

To determine how much bleach and swimming pool shock treatment to mix to obtain 6 cups of a \(7.3\%\) sodium hypochlorite solution, follow these steps: 1. **Define Variables:** - Let \( x \) be the number of cups of bleach (\(5.25\%\) sodium hypochlorite). - Let \( y \) be the number of cups of swimming pool shock treatment (\(10.5\%\) sodium hypochlorite). 2. **Set Up Equations:** - **Total Volume Equation:** \[ x + y = 6 \] - **Sodium Hypochlorite Concentration Equation:** \[ 0.0525x + 0.105y = 0.073 \times 6 \] \[ 0.0525x + 0.105y = 0.438 \] 3. **Solve the System of Equations:** From the total volume equation: \[ y = 6 - x \] Substitute \( y \) into the concentration equation: \[ 0.0525x + 0.105(6 - x) = 0.438 \] \[ 0.0525x + 0.63 - 0.105x = 0.438 \] \[ -0.0525x + 0.63 = 0.438 \] \[ -0.0525x = -0.192 \] \[ x = \frac{0.192}{0.0525} \approx 3.66 \text{ cups} \] Then, find \( y \): \[ y = 6 - 3.66 = 2.34 \text{ cups} \] 4. **Final Answer:** To obtain 6 cups of a \(7.3\%\) sodium hypochlorite mixture, you should mix: - **Approximately 3.66 cups of bleach** - **Approximately 2.34 cups of swimming pool shock treatment** **Rounded to two decimal places:** - **Bleach:** 3.66 cups - **Shock Treatment:** 2.34 cups Answer: To make 6 cups of 7.3% solution, mix approximately 3.66 cups of bleach with 2.34 cups of shock treatment.

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To solve this problem, we can use a system of equations. Let \( x \) be the cups of bleach and \( y \) be the cups of swimming pool shock treatment. We have the following conditions based on the question: 1. The total volume: \[ x + y = 6 \] 2. The concentration of sodium hypochlorite: \[ 0.0525x + 0.105y = 0.073(6) \] Now, calculate the right side of the concentration equation: \[ 0.073 \times 6 = 0.438 \] So, we can rewrite our second equation as: \[ 0.0525x + 0.105y = 0.438 \] Now, we can solve these equations simultaneously. From the first equation, we express \( y \): \[ y = 6 - x \] Substitute \( y \) in the second equation: \[ 0.0525x + 0.105(6 - x) = 0.438 \] \[ 0.0525x + 0.63 - 0.105x = 0.438 \] \[ -0.0525x + 0.63 = 0.438 \] \[ -0.0525x = 0.438 - 0.63 \] \[ -0.0525x = -0.192 \] \[ x = \frac{-0.192}{-0.0525} \approx 3.66 \] Now substitute \( x \) back into the equation for \( y \): \[ y = 6 - x = 6 - 3.66 \approx 2.34 \] Finally, the approximate amounts to mix are: To get 6 cups of a mixture that is \( 7.3\% \) sodium hypochlorite, approximately \( 3.66 \) cups of bleach and approximately \( 2.34 \) cups of swimming pool shock treatment must be mixed.

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