Question
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For the following variables, determine whether \( a \) is a function of \( b, b \) is a function of \( a \), or neither. a is the radius of any U.S. coin and \( b \) is its denomination.

Ask by Dunn Santiago. in the United States
Feb 05,2025

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Tutor-Verified Answer

Answer

\( a \) is a function of \( b \), but \( b \) is not a function of \( a \).

Solution

To determine the relationship between the variables \( a \) (the radius of any U.S. coin) and \( b \) (its denomination), we need to analyze how these two variables interact. 1. **Is \( a \) a function of \( b \)?** - For \( a \) to be a function of \( b \), each denomination \( b \) must correspond to exactly one radius \( a \). - In the U.S., each denomination of coin (e.g., penny, nickel, dime, quarter) has a specific radius. Therefore, for each denomination, there is a unique radius associated with it. - Thus, we can say that \( a \) is a function of \( b \). 2. **Is \( b \) a function of \( a \)?** - For \( b \) to be a function of \( a \), each radius \( a \) must correspond to exactly one denomination \( b \). - However, multiple denominations can have the same radius. For example, both the nickel and the dime have a radius of 1.35 cm. This means that knowing the radius does not uniquely determine the denomination. - Therefore, \( b \) is not a function of \( a \). In conclusion: - \( a \) is a function of \( b \). - \( b \) is not a function of \( a \).

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The Deep Dive

In the world of U.S. coins, each denomination corresponds to a specific radius, such as a penny or a quarter. This means that given a denomination \( b \), you can always find a unique radius \( a \) for that coin. So in this case, \( a \) is a function of \( b \). On the flip side, if you consider the radius \( a \), multiple denominations can share the same radius, especially in cases like the nickel and the dime. Hence, \( b \) is not a function of \( a \). Coins do not uniquely map back to one specific denomination based solely on radius.

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