Find the $$ x $$ - and $$ y $$-intercepts of the line. $$ y=-4 x-2 $$ $$ x $$-intercept $$ \quad(x, y)=(\square) $$ $$ y $$-intercept $$ \quad(x, y)=(\square) $$

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To find the $$ x $$- and $$ y $$-intercepts of the line given by the equation:

$$
y = -4x - 2
$$

### $$ y $$-Intercept

The $$ y $$-intercept occurs where the line crosses the $$ y $$-axis. At this point, the value of $$ x $$ is $$ 0 $$.

1. **Set $$ x = 0 $$ in the equation:**

$$
   y = -4(0) - 2 = -2
   $$

2. **Therefore, the $$ y $$-intercept is:**

$$
   (x, y) = (0, -2)
   $$

### $$ x $$-Intercept

The $$ x $$-intercept occurs where the line crosses the $$ x $$-axis. At this point, the value of $$ y $$ is $$ 0 $$.

1. **Set $$ y = 0 $$ in the equation and solve for $$ x $$:**

$$
   0 = -4x - 2
   $$
   
   $$
   4x = -2
   $$
   
   $$
   x = -\frac{2}{4} = -\frac{1}{2}
   $$

2. **Therefore, the $$ x $$-intercept is:**

$$
   (x, y) = \left( -\frac{1}{2}, \ 0 \right)
   $$

### Summary

- **$$ x $$-intercept:** $$ \left( -\dfrac{1}{2}, \ 0 \right) $$
- **$$ y $$-intercept:** $$ (0, -2) $$
$$ x $$-intercept: $$ \left( -\dfrac{1}{2}, \ 0 \right) $$, $$ y $$-intercept: $$ (0, -2) $$.

Find the \( x \) - and \( y \)-intercepts of the line. \[ y=-4 x-2 \] \( x \)-intercept \( \quad(x, y)=(\square) \) \( y \)-intercept \( \quad(x, y)=(\square) \)

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