For this problem, recall that $$ \sin ^{2} heta $$ means $$ (\sin heta)^{2} $$ $$ \sin heta=\frac{4}{\sqrt{17}} $$, find $$ \sin ^{2} heta $$ $$ \sin ^{2} heta=\square $$

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For this problem, recall that $$ \sin ^{2} 	heta $$ means $$ (\sin 	heta)^{2} $$ $$ \sin 	heta=\frac{4}{\sqrt{17}} $$, find $$ \sin ^{2} 	heta $$ $$ \sin ^{2} 	heta=\square $$

UpStudy AI · Accepted Answer

Given that $$ \sin 	heta = \frac{4}{\sqrt{17}} $$, we need to find $$ \sin ^{2} 	heta $$.

To find $$ \sin ^{2} 	heta $$, we can simply square the value of $$ \sin 	heta $$.

Therefore, $$ \sin ^{2} 	heta = \left(\frac{4}{\sqrt{17}}ight)^{2} $$.

Now, let's calculate the value of $$ \sin ^{2} 	heta $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\left(\frac{4}{\sqrt{17}}ight)^{2}$$
- step1: Use the properties of exponents:
  $$\frac{4^{2}}{\left(\sqrt{17}ight)^{2}}$$
- step2: Evaluate the power:
  $$\frac{16}{\left(\sqrt{17}ight)^{2}}$$
- step3: Evaluate the power:
  $$\frac{16}{17}$$
The value of $$ \sin ^{2} 	heta $$ is $$ \frac{16}{17} $$ or approximately 0.941176.
$$ \sin ^{2} 	heta = \frac{16}{17} $$

For this problem, recall that \( \sin ^{2} \theta \) means \( (\sin \theta)^{2} \) \( \sin \theta=\frac{4}{\sqrt{17}} \), find \( \sin ^{2} \theta \) \( \sin ^{2} \theta=\square \)

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