Find the $$ z $$ value to the right of the mean so that $$ 79.95 \% $$ of the area under the distribution curve lies to the left of it. Use The Standard Normal Distribution Table and enter the answer to 2 decimal places. $$ z= $$

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We need to find $$ z $$ such that

$$
P(Z < z)=0.7995.
$$

1. Look up in the Standard Normal Distribution Table for the area closest to $$ 0.7995 $$. In many tables, the value $$ 0.7995 $$ corresponds to $$ z=0.84 $$.

2. Thus, based on the table, we have

$$
z \approx 0.84.
$$

So the $$ z $$ value to the right of the mean that leaves $$ 79.95\% $$ of the area to its left is

$$
z = 0.84.
$$
$$ z = 0.84 $$

Find the value to the right of the mean so that of the area under the distribution curve lies to the left of it. Use
The Standard Normal Distribution Table and enter the answer to 2 decimal places.

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Find the value to the right of the mean so that of the area under the distribution curve lies to the left of it. Use The Standard Normal Distribution Table and enter the answer to 2 decimal places.