Determine the full flow velocity of wastewater (accurate to 2 dec.pl.) in a concrete sewer with a diameter of 425 mm and a slope of \( 0.017 \mathrm{~m} / \mathrm{m} \).
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To determine the full flow velocity of wastewater in a concrete sewer, we can utilize the Manning's equation, which is commonly used for open channel flow. The equation is: \[ V = \frac{1}{n} R^{2/3} S^{1/2} \] Where: - \( V \) is the flow velocity (m/s) - \( n \) is the Manning's roughness coefficient (for concrete, approximately 0.013) - \( R \) is the hydraulic radius (m) - \( S \) is the slope of the energy grade line (dimensionless, given as 0.017) First, we calculate the hydraulic radius \( R \). For a full circular sewer: \[ R = \frac{A}{P} \] Where: - \( A \) is the area of flow (m²) = \( \frac{\pi D^2}{4} \) - \( P \) is the wetted perimeter (m) = \( D \) Given a diameter \( D = 0.425 \, \text{m} \): 1. Calculate the area \( A \): \[ A = \frac{\pi (0.425)^2}{4} \approx 0.140 \, m^2 \] 2. Calculate the wetted perimeter \( P \): \[ P = D = 0.425 \, m \] 3. Now calculate hydraulic radius \( R \): \[ R = \frac{A}{P} = \frac{0.140}{0.425} \approx 0.329\, m \] Now substituting into Manning's equation: \[ n = 0.013 \] \[ S = 0.017 \] \[ V = \frac{1}{0.013} (0.329)^{2/3} (0.017)^{1/2} \] Calculating each component, \[ (0.329)^{2/3} \approx 0.248 \] \[ (0.017)^{1/2} \approx 0.130 \] Now substituting back into the equation: \[ V \approx \frac{1}{0.013} \times 0.248 \times 0.130 \approx \frac{0.0042336}{0.013} \approx 0.326 \, m/s \] Thus, the full flow velocity of the wastewater in the sewer is \( \approx 0.33 \, m/s \) when accurate to 2 decimal places.