A container with a length of
40 cm , a breadth of 30 cm
and a height of 10 cm
contains 12 identical cans
with a diameter of 10 cm
and a height of 10 cm . The
remaining space is filled
with a thick liquid. How
much liquid was required to
fill the gaps of the
container?

First, let’s calculate the volume of the container. The volume is given by the formula: Volume = length × breadth × height. This gives us 40 cm × 30 cm × 10 cm = 12,000 cm³.

Next, we find the volume occupied by the cans. The volume of one can is given by the formula for the volume of a cylinder: Volume = π × (radius)² × height. Since the diameter is 10 cm, the radius is 5 cm. Thus, the volume of one can is approximately 3.14 × (5 cm)² × 10 cm ≈ 785 cm³. For 12 cans, the total volume is 12 × 785 cm³ ≈ 9,420 cm³.

Finally, we subtract the volume of the cans from the volume of the container: 12,000 cm³ - 9,420 cm³ = 2,580 cm³. Therefore, the volume of the thick liquid required to fill the gaps of the container is 2,580 cm³.