Find the slope and reduce. \[ \begin{array}{c}P=(-2,3) \mathrm{Q}=(8,3) \\ \text { Slope }=[?]\end{array} \]

To find the slope between points P=(-2, 3) and Q=(8, 3), we use the slope formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] In this case, \(P\) is \( (x_1, y_1) = (-2, 3)\) and \(Q\) is \( (x_2, y_2) = (8, 3)\). Plugging in the values: \[ m = \frac{3 - 3}{8 - (-2)} = \frac{0}{8 + 2} = \frac{0}{10} = 0 \] The slope is 0, indicating that the line connecting points P and Q is horizontal. Since the slope is already in its simplest form, there’s nothing to reduce!