Lian Mousa In $$ riangle J K L, \mathrm{~m} \angle L=90^{\circ} $$. If $$ \sin J=0.6 $$, what is the value of $$ \cos K $$ to the nearest tenth? Enter the correct answer in the box.

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Lian Mousa In $$ 	riangle J K L, \mathrm{~m} \angle L=90^{\circ} $$. If $$ \sin J=0.6 $$, what is the value of $$ \cos K $$ to the nearest tenth? Enter the correct answer in the box.

UpStudy AI · Accepted Answer

The triangle $$ \triangle JKL $$ is a right triangle with $$ \angle L = 90^\circ $$. Since $$ \sin J = 0.6 $$, we can determine $$ \cos K $$ using the fact that angles $$ J $$ and $$ K $$ are complementary (i.e., $$ J + K = 90^\circ $$).

In a right triangle, the sine of one acute angle is equal to the cosine of the other acute angle. Therefore:
$$
\cos K = \sin J = 0.6
$$

**Answer:**  
0.6
$$ \cos K = 0.6 $$

Lian Mousa
In . If , what is the value of to the nearest tenth?
Enter the correct answer in the box.

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Lian Mousa In . If , what is the value of to the nearest tenth? Enter the correct answer in the box.