Question
\( \begin{array}{l}\text { What is the value of } x \text { after the following statements? } \\ \text { int } x, y, z \\ y=10 ; \\ z=3 ; \\ x=y^{\prime} z+3 ;\end{array} \) 33 30
Ask by Hobbs Edwards. in the United States
Jan 21,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
After executing the code, the value of `x` is 33.
Solution
Let's analyze the provided code step by step to determine the value of `x` after the execution:
```c
int x, y, z;
y = 10;
z = 3;
x = y * z + 3;
```
1. **Declaration:**
```c
int x, y, z;
```
- Three integer variables `x`, `y`, and `z` are declared.
2. **Assignment to `y`:**
```c
y = 10;
```
- The variable `y` is assigned the value `10`.
3. **Assignment to `z`:**
```c
z = 3;
```
- The variable `z` is assigned the value `3`.
4. **Calculation and Assignment to `x`:**
```c
x = y * z + 3;
```
- First, multiply `y` and `z`: `10 * 3 = 30`.
- Then, add `3` to the result: `30 + 3 = 33`.
- The variable `x` is assigned the value `33`.
**Final Value:**
- After executing all the statements, the value of `x` is **33**.
**Answer:** 33
Reviewed and approved by the UpStudy tutoring team
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Simplify this solution Extra Insights
In the given statements, the value of \( y' \) is a bit mysterious! Assuming \( y' \) is intended as \( y \) (commonly used in programming to denote a variable), if we calculate \( x \) as \( x = y \cdot z + 3 \), substituting the values gives \( x = 10 \cdot 3 + 3 = 30 + 3 \), which equals 33. Double-checking with erroneous input: If \( y' \) somehow represents another operation or transformation (for instance, negation or bitwise NOT), you'd end up with a different result. In coding, clarity is key to avoid these confusions!
