b) $$ an 405^{\circ}- an (\arctan 1)= $$

Question

b) $$ 	an 405^{\circ}-	an (\arctan 1)= $$

UpStudy AI · Accepted Answer

1. Recognize that $$405^\circ = 360^\circ + 45^\circ$$. Since the tangent function has a period of $$180^\circ$$, we have
   $$
   \tan 405^\circ = \tan (360^\circ + 45^\circ) = \tan 45^\circ.
   $$

2. We know that
   $$
   \tan 45^\circ = 1.
   $$

3. Additionally, by the definition of the arctan function,
   $$
   \tan (\arctan 1) = 1.
   $$

4. Substitute these results into the original expression:
   $$
   \tan 405^\circ - \tan (\arctan 1) = 1 - 1 = 0.
   $$
The result is 0.

b)

Upstudy AI Solution

Answer

Solution

Bonus Knowledge

Related Questions

Latest Trigonometry Questions