Find $$ f(-1) $$ for the piece-wise function. $$ f(x)=\left\{\begin{array}{ll}x+2 & ext { if } x \leq-1 \ 2 x+4 & ext { if } x-1\end{array} ight. $$ $$ f(-1)=[?] $$

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Find $$ f(-1) $$ for the piece-wise function. $$ f(x)=\left\{\begin{array}{ll}x+2 & 	ext { if } x \leq-1 \ 2 x+4 & 	ext { if } x>-1\end{array}ight. $$ $$ f(-1)=[?] $$

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Para encontrar $$ f(-1) $$ de la función definida por partes:

$$
f(x) = \begin{cases} 
x + 2 & \text{si } x \leq -1 \
2x + 4 & \text{si } x > -1 
\end{cases}
$$

Evaluamos en $$ x = -1 $$:

1. **Determinar la rama aplicable:**
   - Dado que $$ -1 \leq -1 $$, usamos la primera parte de la función: $$ f(x) = x + 2 $$.

2. **Calcular $$ f(-1) $$:**
   $$
   f(-1) = (-1) + 2 = 1
   $$

Por lo tanto:

$$
f(-1) = 1
$$
$$ f(-1) = 1 $$

Find \( f(-1) \) for the piece-wise function. \( f(x)=\left\{\begin{array}{ll}x+2 & \text { if } x \leq-1 \\ 2 x+4 & \text { if } x>-1\end{array}\right. \) \( f(-1)=[?] \)

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