Before the area between these two functions can be found, they must be made functions of the same variable. $$ \begin{array}{c}\text { Convert } g(x) \text { into } g(y) \ \qquad \ f(y)=3 y^{2}-3 \ g(x)=\frac{x-5}{2} \ g(y)=[?] y+[ \end{array} $$

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To convert $$ g(x) $$ into $$ g(y) $$, we need to express $$ x $$ in terms of $$ y $$ using the equation for $$ g(x) $$.

Given:
$$
g(x) = \frac{x - 5}{2}
$$

We can rearrange this equation to solve for $$ x $$:
1. Multiply both sides by 2:
   $$
   2g(x) = x - 5
   $$
2. Add 5 to both sides:
   $$
   x = 2g(x) + 5
   $$

Now, we can substitute $$ g(y) $$ for $$ g(x) $$ in the equation:
$$
g(y) = \frac{y - 5}{2}
$$

Thus, we can express $$ g(y) $$ as:
$$
g(y) = \frac{y - 5}{2}
$$

Now, let's write it in the required format:
$$
g(y) = \frac{1}{2}y - \frac{5}{2}
$$

So, the final expression for $$ g(y) $$ is:
$$
g(y) = \frac{1}{2}y - \frac{5}{2}
$$
$$ g(y) = \frac{1}{2}y - \frac{5}{2} $$

Before the area between these two
functions can be found, they must be
made functions of the same variable.

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