Solve for \( x \) e. \( x \times 1=x \) f. \( 1 \times 54=x \) \( 3 \cdot a, x+15=15+10 \) b. \( x \times 7 \times 2=5 \times 2 \times 7 \) c. \( 14 \times 11 \times 2=28 \times x \)

Certainly! Let's solve each of the given equations for \( x \) step by step. --- ### **e. \( x \times 1 = x \)** **Solution:** Multiplying any number by 1 leaves the number unchanged. Therefore: \[ x \times 1 = x \] This equation holds true for **all real numbers** \( x \). There's no specific value to solve for since \( x \) can be any real number. --- ### **f. \( 1 \times 54 = x \)** **Solution:** Calculate the left side: \[ 1 \times 54 = 54 \] So, \[ x = 54 \] **Answer:** \( x = 54 \) --- ### **\( x + 15 = 15 + 10 \)** **Solution:** Simplify the right side: \[ x + 15 = 25 \] Subtract 15 from both sides to solve for \( x \): \[ x = 25 - 15 \] \[ x = 10 \] **Answer:** \( x = 10 \) --- ### **b. \( x \times 7 \times 2 = 5 \times 2 \times 7 \)** **Solution:** First, simplify both sides: \[ x \times 7 \times 2 = 14x \] \[ 5 \times 2 \times 7 = 70 \] Set the simplified expressions equal to each other: \[ 14x = 70 \] Divide both sides by 14 to solve for \( x \): \[ x = \frac{70}{14} \] \[ x = 5 \] **Answer:** \( x = 5 \) --- ### **c. \( 14 \times 11 \times 2 = 28 \times x \)** **Solution:** First, calculate the left side: \[ 14 \times 11 = 154 \] \[ 154 \times 2 = 308 \] So the equation becomes: \[ 308 = 28x \] Divide both sides by 28 to solve for \( x \): \[ x = \frac{308}{28} \] \[ x = 11 \] **Answer:** \( x = 11 \) --- ### **Summary of Solutions:** - **e.** Any real number \( x \) satisfies \( x \times 1 = x \). - **f.** \( x = 54 \) - **\( x + 15 = 25 \)**: \( x = 10 \) - **b.** \( x = 5 \) - **c.** \( x = 11 \) If you have any further questions or need additional assistance, feel free to ask!