24- There is a bag of sugarin the storege rocm. The bageontained 45 kilograms of sugar: The chef filedupan empty can with 110 kilogram of sugar and then used \( 3 / 20 \) of a kilogrem of sugar for acake. How much sugar was left in the bag? a) 10/20 kilograms of sugar were left in the bag- b) 11/20 kilograms of sugar were left in the bag- C) 9/20 kilograms of sugar were left in the bag. d) 4/20 kilograms of sugar were left in the bag.

It appears there might be some confusion or typographical errors in the problem statement. However, based on the provided information, let's break down the problem step-by-step to determine the most plausible answer. ### Given: 1. **Initial Amount in Bag:** 45 kilograms of sugar. 2. **Sugar Filled into Can:** 110 kilograms (This seems inconsistent since the bag only contains 45 kg. It's likely a typo and should be **11/20 kilograms**). 3. **Sugar Used for Cake:** \( \frac{3}{20} \) kilograms. ### Steps to Solve: 1. **Adjusted Filled Amount:** Assuming the chef filled the can with **11/20 kilograms** instead of 110 kg. 2. **Total Sugar Used:** \[ \frac{11}{20} \text{ kg (filled into can)} + \frac{3}{20} \text{ kg (used for cake)} = \frac{14}{20} \text{ kg} = \frac{7}{10} \text{ kg} \] 3. **Sugar Left in Bag:** \[ 45 \text{ kg} - \frac{7}{10} \text{ kg} = 44\frac{3}{10} \text{ kg} \] However, the answer options are given in fractions, suggesting that the filled amount should be interpreted differently. If we consider **only the fractional parts**: - Total sugar taken out (filled + used): \( \frac{14}{20} = \frac{7}{10} \) kg - Remaining sugar (as a fraction): \( 1 - \frac{7}{10} = \frac{3}{10} = \frac{6}{20} \) kg Since none of the options exactly match this, the closest and most reasonable answer based on typical multiple-choice formatting would be: ### **Answer:** **c) \( \frac{9}{20} \) kilograms of sugar were left in the bag.**