The admission fee at an amusement park is \( \$ 4.00 \) for children and \( \$ 4.80 \) for adults. On a certain day, 220 people entered the park, and the admission fees collected totaled \( \$ 976 \). How many children and how many adults were admitted? Number of children: Number of adults:

First, let's denote the number of children as \( c \) and the number of adults as \( a \). We have the following system of equations based on the problem: 1. \( c + a = 220 \) (the total number of people) 2. \( 4c + 4.80a = 976 \) (the total admission fees collected) Now, we can solve this system step by step. From the first equation, we can express \( a \) in terms of \( c \): \[ a = 220 - c \] Substituting this expression for \( a \) into the second equation gives: \[ 4c + 4.80(220 - c) = 976 \] Expanding this: \[ 4c + 1056 - 4.80c = 976 \] Combining like terms: \[ -0.80c + 1056 = 976 \] Subtracting 1056 from both sides: \[ -0.80c = -80 \] Dividing by -0.80: \[ c = 100 \] Now substituting \( c = 100 \) back into the equation \( a = 220 - c \): \[ a = 220 - 100 = 120 \] So, the solution is: Number of children: 100 Number of adults: 120