Calculate the mean, the median, and the mode for each of the following data sets. a. \( 3,7,7,8,6,7,12,4 \) b. \( 10.5,12.5,12.5,14.5,19.5,16.5,12.5,14.5,11.5 \) c. \( 5,-4.2,-5.4,6.2,0,3.2,10.3,0.9 \) d. \( 74,79,87,79,73,76,5 \) a. The mean is \( \square \). (Round to the nearest thousandth as needed.)

To calculate the mean, median, and mode for each dataset: **a.** Mean: \(\frac{3 + 7 + 7 + 8 + 6 + 7 + 12 + 4}{8} = \frac{54}{8} = 6.75\) Median: When arranged \(3, 4, 6, 7, 7, 7, 8, 12\), the middle values are \(7\) and \(7\), so the median is \(7\). Mode: \(7\) (it appears most frequently). **b.** Mean: \(\frac{10.5 + 12.5 + 12.5 + 14.5 + 19.5 + 16.5 + 12.5 + 14.5 + 11.5}{9} = \frac{130.5}{9} = 14.5\) Median: Arranging \(10.5, 11.5, 12.5, 12.5, 12.5, 14.5, 14.5, 16.5, 19.5\), the middle value is \(12.5\). Mode: \(12.5\) (it appears most frequently). **c.** Mean: \(\frac{5 + (-4.2) + (-5.4) + 6.2 + 0 + 3.2 + 10.3 + 0.9}{8} = \frac{16}{8} = 2.0\) Median: Arranging \(-5.4, -4.2, 0, 0.9, 3.2, 5, 6.2, 10.3\), the median is \(0.9\). Mode: No mode (all numbers appear once). **d.** Mean: \(\frac{74 + 79 + 87 + 79 + 73 + 76 + 5}{7} = \frac{473}{7} = 67.571\) (rounded to 3 decimal places) Median: Arranging \(5, 73, 74, 76, 79, 79, 87\), the middle value is \(76\). Mode: \(79\) (it appears most frequently). Feel free to ask if you need help with anything else!