Use the ordinary annuity formula shown to the right to determine the accumulated amount in the annulty if $$ \$ 50 $$ is invested semlannually for 25 years at $$ 3.5 \% $$ compounded semiannually. $$ \quad \mathrm{A}=\frac{\mathrm{r}}{\mathrm{n}}\left[\left(1+\frac{\mathrm{r}}{\mathrm{n}}\right)^{\mathrm{nt}}-1\right]^{\mathrm{r}} $$

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Calculate or simplify the expression $$ (0.035/2)*(1+(0.035/2))^(2*25)-1 $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\left(\frac{0.035}{2}ight)\left(1+\left(\frac{0.035}{2}ight)ight)^{2	imes 25}-1$$
- step1: Divide the terms:
  $$\left(\frac{0.035}{2}ight)\left(1+\frac{7}{400}ight)^{2	imes 25}-1$$
- step2: Add the numbers:
  $$\left(\frac{0.035}{2}ight)\left(\frac{407}{400}ight)^{2	imes 25}-1$$
- step3: Divide the terms:
  $$\frac{7}{400}\left(\frac{407}{400}ight)^{2	imes 25}-1$$
- step4: Multiply the numbers:
  $$\frac{7}{400}\left(\frac{407}{400}ight)^{50}-1$$
- step5: Multiply the numbers:
  $$\frac{7	imes 407^{50}}{400^{51}}-1$$
- step6: Reduce fractions to a common denominator:
  $$\frac{7	imes 407^{50}}{400^{51}}-\frac{400^{51}}{400^{51}}$$
- step7: Transform the expression:
  $$\frac{7	imes 407^{50}-400^{51}}{400^{51}}$$
The accumulated amount in the annuity is approximately $-0.958336.
The accumulated amount is approximately $-0.958336.

Use the ordinary annuity formula shown to the right to determine the accumulated amount in
the annulty if is invested semlannually for 25 years at compounded semiannually.

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Use the ordinary annuity formula shown to the right to determine the accumulated amount in the annulty if is invested semlannually for 25 years at compounded semiannually.