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Factorize the following algebraic in \( 7 x^{2}-63 \)

Ask by Graham Weaver. in Pakistan
Feb 04,2025

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Tutor-Verified Answer

Answer

\( 7x^{2} - 63 = 7(x - 3)(x + 3) \)

Solution

To factorize the algebraic expression \( 7x^{2} - 63 \), follow these steps: 1. **Factor Out the Greatest Common Factor (GCF):** Both terms in the expression \( 7x^{2} - 63 \) have a common factor of **7**. Factor out the 7: \[ 7x^{2} - 63 = 7(x^{2}) - 7(9) = 7(x^{2} - 9) \] 2. **Recognize the Difference of Squares:** The expression inside the parentheses, \( x^{2} - 9 \), is a **difference of squares**. Recall that: \[ a^{2} - b^{2} = (a - b)(a + b) \] Here, \( a = x \) and \( b = 3 \) (since \( 3^{2} = 9 \)). 3. **Apply the Difference of Squares Formula:** Apply the formula to \( x^{2} - 9 \): \[ x^{2} - 9 = (x - 3)(x + 3) \] 4. **Combine the Factors:** Substitute back into the expression with the factored-out 7: \[ 7(x^{2} - 9) = 7(x - 3)(x + 3) \] **Final Factored Form:** \[ 7x^{2} - 63 = 7(x - 3)(x + 3) \]

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To factor the expression \( 7x^{2} - 63 \), start by identifying the greatest common factor (GCF), which is 7. Factoring out the GCF gives us: \[ 7(x^{2} - 9) \] Now, notice that \( x^{2} - 9 \) is a difference of squares, which can be further factored as: \[ 7(x - 3)(x + 3) \] So, the fully factored form of \( 7x^{2} - 63 \) is \( 7(x - 3)(x + 3) \). Factoring isn't just an academic exercise; it has real-world applications in areas like physics and engineering, where equations are often simplified to make calculations easier. By breaking down complex equations into manageable parts, professionals can solve problems more efficiently and effectively, ensuring better outcomes in design and analysis! Misplacing a negative sign or skipping steps in the factorization process can lead to incorrect results. Always double-check your work, especially with the difference of squares, which can be tricky! A fun tip is to remember the pattern: \( a^2 - b^2 = (a - b)(a + b) \) – visualize it as two kids tugging at opposite ends of a rope, each ready to pull in their own direction!

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