Simplify. \( \left(7 y^{2}+3\right)-\left(2 y^{2}-4 y+5\right) \) \( \square \)

To simplify the expression \( \left(7 y^{2}+3\right)-\left(2 y^{2}-4 y+5\right) \), we start by distributing the negative sign across the second group: \[ 7y^2 + 3 - 2y^2 + 4y - 5 \] Now, combine like terms: 1. For \(y^2\) terms: \(7y^2 - 2y^2 = 5y^2\) 2. For \(y\) terms: \(4y\) (there's only one \(y\) term) 3. For constants: \(3 - 5 = -2\) Putting it all together, we get: \[ 5y^2 + 4y - 2 \] So, the simplified expression is \(5y^2 + 4y - 2\).