Question
upstudy study bank question image url

Probability A bag of miniature candy contains: - 15 Crunch bars - 14 Hershey's chocolate bars - 10 Mr . Goodbars - 12 Hershey's Cookies and Cream bars. Enter all answers as reduced fractions using / as the fraction bar. 1. What is the probability of randomly choosing a Crunch bar? \( P(R)= \) 2. What is the probability of randomly choosing a Mr. Goodbar? \( P(G)= \) 3. What is the probability of randomly choosing a Cookies and Cream bar? \( P(K)= \)

Ask by Malone Bowers. in the United States
Feb 03,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

1. \( P(R) = \frac{5}{17} \) 2. \( P(G) = \frac{10}{51} \) 3. \( P(K) = \frac{4}{17} \)

Solution

Sure, let's calculate each probability step by step. **Total number of candies:** \[ 15 \text{ (Crunch)} + 14 \text{ (Hershey's)} + 10 \text{ (Mr. Goodbars)} + 12 \text{ (Cookies and Cream)} = 51 \] 1. **Probability of choosing a Crunch bar \( P(R) \):** \[ P(R) = \frac{15}{51} \] \[ \text{Simplify the fraction by dividing numerator and denominator by 3:} \] \[ P(R) = \frac{5}{17} \] 2. **Probability of choosing a Mr. Goodbar \( P(G) \):** \[ P(G) = \frac{10}{51} \] \[ \text{This fraction is already in its simplest form.} \] 3. **Probability of choosing a Cookies and Cream bar \( P(K) \):** \[ P(K) = \frac{12}{51} \] \[ \text{Simplify the fraction by dividing numerator and denominator by 3:} \] \[ P(K) = \frac{4}{17} \] **Final Answers:** 1. \( P(R) = \frac{5}{17} \) 2. \( P(G) = \frac{10}{51} \) 3. \( P(K) = \frac{4}{17} \)

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Mind Expander

To find the probabilities, we first need to calculate the total number of candy bars in the bag. Total bars = 15 (Crunch) + 14 (Hershey's) + 10 (Mr. Goodbar) + 12 (Cookies and Cream) = 51. Now we can calculate the probabilities: 1. The probability of randomly choosing a Crunch bar: \( P(R) = \frac{15}{51} \) which simplifies to \( \frac{5}{17} \). 2. The probability of randomly choosing a Mr. Goodbar: \( P(G) = \frac{10}{51} \) which is already in its simplest form. 3. The probability of randomly choosing a Cookies and Cream bar: \( P(K) = \frac{12}{51} \) which simplifies to \( \frac{4}{17} \). Now, deep dive into the candy world! The rich history of these iconic candy bars dates back decades, with some of them like Crunch being introduced as far back as 1936! Despite their initial popularity, they've kept their charm by adapting to changing tastes over the years, keeping candy lovers coming back for more. Speaking of candy, did you know that understanding probability can also help in real-life decisions? For example, if you’re at a party with a variety of snacks, knowing your favorite treats' odds can help you strategize how to grab the most desirable ones before they disappear! So math isn’t just for the classroom; it can lead to some sweet victories!

Related Questions

Latest Probability Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy