Multiply. \[ (x+5 w+2)(4 x-5 w) \] Simplify. your answer. पI
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To multiply the expressions \((x+5)(w+2)(4x-5w)\), we'll apply the distributive property, also known as the FOIL method for binomials. First, distribute \((x + 5)(w + 2)\): \[ = x(w + 2) + 5(w + 2) \\ = xw + 2x + 5w + 10 \] Now, we have \(xw + 2x + 5w + 10\). Next, we'll multiply this result by \((4x - 5w)\): \[ = (xw + 2x + 5w + 10)(4x - 5w) \] Distributing \(4x\) and \(-5w\) to each term: \[ = 4x(xw) + 4x(2x) + 4x(5w) + 4x(10) - 5w(xw) - 5w(2x) - 5w(5w) - 5w(10) \] This results in: \[ = 4x^2w + 8x^2 + 20x + 40x - 5w^2x - 10wx - 25w^2 - 50w \] Now, combine like terms: \[ = (4x^2w - 5w^2x) + (8x^2 - 10wx) + (20x - 25w^2 - 50w) \] Putting together common terms, our final expression simplifies to: \[ = 4x^2w - 5w^2x + 8x^2 - 10wx + 20x - 25w^2 - 50w \] This is a simplified version of the product \((x+5)(w+2)(4x-5w)\).