c. Lauren invests R3 500 at $$ 4,5 \% $$ p.a. simple interest. After a certain amount of years, it grew to R 4602,50 . Calculate the number of years it took to grow to R 4602,50. A. 5 B. 6 C. 7 D. 8.

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To find the number of years it took for Lauren's investment to grow from R3,500 to R4,602.50 at a simple interest rate of 4.5% per annum, we can use the formula for simple interest:

$$
A = P(1 + rt)
$$

Where:
- $$ A $$ is the final amount (R4,602.50)
- $$ P $$ is the principal amount (R3,500)
- $$ r $$ is the rate of interest (4.5% or 0.045)
- $$ t $$ is the time in years

We can rearrange the formula to solve for $$ t $$:

$$
t = \frac{A - P}{Pr}
$$

Now, substituting the values into the formula:

$$
t = \frac{4602.50 - 3500}{3500 \times 0.045}
$$

Calculating the numerator:

$$
4602.50 - 3500 = 1102.50
$$

Calculating the denominator:

$$
3500 \times 0.045 = 157.5
$$

Now, substituting these values back into the equation for $$ t $$:

$$
t = \frac{1102.50}{157.5} \approx 7
$$

Thus, the number of years it took for the investment to grow to R4,602.50 is approximately 7 years.

The answer is **C. 7**.
The number of years it took for the investment to grow to R4,602.50 is 7 years.

c. Lauren invests R3 500 at p.a. simple interest. After a
certain amount of years, it grew to R 4602,50 . Calculate the
number of years it took to grow to R 4602,50.
A. 5
B. 6
C. 7
D. 8.

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c. Lauren invests R3 500 at p.a. simple interest. After a certain amount of years, it grew to R 4602,50 . Calculate the number of years it took to grow to R 4602,50. A. 5 B. 6 C. 7 D. 8.