\( 1 \leftarrow \quad \begin{array}{l}\text { Graph the equation and identify the } y \text {-intercept. } \\ \quad x+3 y=6\end{array} \)

To graph the equation \( x + 3y = 6 \), first, rearrange it into slope-intercept form, \( y = mx + b \). Solving for \( y \) gives \( y = -\frac{1}{3}x + 2 \). This tells us the slope is \(-\frac{1}{3}\) and the y-intercept is \(2\). To graph, you can plot the y-intercept at \((0, 2)\) and use the slope to find another point. Moving down \(1\) unit and right \(3\) units from \((0, 2)\) reaches \((3, 1)\). Connect these points to complete the graph! Don’t forget, the y-intercept is where the graph crosses the y-axis, which is at the point \((0, 2)\)! It’s where \(x = 0\), so you can just plug in \(x = 0\) in the original equation to double-check: \(0 + 3y = 6\) simplifies to \(y = 2\). Voila, the intersection confirms your findings!