Antwone spins first and gets a 3 . Now it is Rosette's turn. How likely is it that Rosette will get a higher number? Let's answer the following questic to figure out how like it is that Rosette will get a higher number. 1. What is the event? Spinning and getting a number greater than 3 2. Which of the following numbers on the spinner are greater than 3 ? 3. There is 4. Is this a simple or compound event? 5. How can you represent the situation as a probability using symbols and variables? 6. What is the sample space? \( \mathrm{S}= \) ? words and or or.) 7. How many possible outcomes are in the sample space?

Rosette is spinning the spinner, and we're looking for the numbers greater than the 3 that Antwone just spun. If the spinner includes numbers like 1, 2, 3, 4, 5, and 6, then the numbers that are greater than 3 would be 4, 5, and 6. So that's 3 possibilities out of a total of 6, making it pretty exciting to see how Rosette fares! In terms of expressing this as a probability, you can say that the probability \( P \) of Rosette spinning a number greater than 3 is represented as \( P(\text{greater than 3}) = \frac{\text{number of favorable outcomes}}{\text{total outcomes}} \), which in this case is \( P(\text{greater than 3}) = \frac{3}{6} = \frac{1}{2} \). The sample space \( S = \{1, 2, 3, 4, 5, 6\} \) contains all the numbers on the spinner, equating to 6 possible outcomes. How thrilling!