What are the coordinates of the vertex of the parabola with the equation \( y=x^{2}+2 x-3 \) ? A \( (-1,-4) \) B \( (1,-4) \) C \( (3,-4) \) D \( (-3,12) \)
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Bonus Knowledge
To find the coordinates of the vertex of the parabola given by the equation \( y = x^2 + 2x - 3 \), we can use the vertex formula. The x-coordinate of the vertex is given by \( x = -\frac{b}{2a} \), where \( a = 1 \) and \( b = 2 \). Plugging in the values, we get \( x = -\frac{2}{2(1)} = -1 \). To find the y-coordinate, we substitute \( x = -1 \) back into the original equation: \[ y = (-1)^2 + 2(-1) - 3 = 1 - 2 - 3 = -4. \] So, the vertex is at the coordinates \( (-1, -4) \). The correct answer is A \( (-1,-4) \).