\[ \begin{array}{l}\text { Boodwork code sc } \\ \text { At a diving competition, five judges each score a dive } \\ \text { out of } 10 \text {. } \\ \text { The five scores are then added together and } \\ \text { multiplied by the difficulty rating to give the final } \\ \text { score. } \\ \text { The judge's scores for a dive with a difficulty rating of } \\ 3.6 \text { are shown. } \\ \text { What was the final score? }\end{array} . \]

To find the final score of the dive, we first need to add the scores from the five judges together. Let's say the judges' scores are \(S_1, S_2, S_3, S_4, S_5\). Once you have the total score \(T\) from the judges, you calculate it as follows: \[ T = S_1 + S_2 + S_3 + S_4 + S_5 \] Then, to find the final score \(F\), multiply the total score \(T\) by the difficulty rating \(D\), which in this case is \(3.6\): \[ F = T \times D \] For example, if the judges scored \(8, 9, 7, 10, 6\), then: \[ T = 8 + 9 + 7 + 10 + 6 = 40 \] And the final score would be: \[ F = 40 \times 3.6 = 144 \] So, just add the scores first, then multiply by the difficulty rating to get the final score!