Find the \( y \)-intercept and \( x \)-intercept of the line. \( 4 x-3 y=-5 \) \( y \)-intercept: \( \square \) \( x \)-intercept: \( \square \)
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To find the \( y \)-intercept, set \( x = 0 \) in the equation \( 4x - 3y = -5 \). This gives \( 4(0) - 3y = -5 \) or \( -3y = -5 \), resulting in \( y = \frac{5}{3} \). Therefore, the \( y \)-intercept is \( \left( 0, \frac{5}{3} \right) \). To find the \( x \)-intercept, set \( y = 0 \) in the same equation. This yields \( 4x - 3(0) = -5 \) or \( 4x = -5 \), resulting in \( x = -\frac{5}{4} \). Thus, the \( x \)-intercept is \( \left( -\frac{5}{4}, 0 \right) \). \( y \)-intercept: \( \left( 0, \frac{5}{3} \right) \) \( x \)-intercept: \( \left( -\frac{5}{4}, 0 \right) \)