Question
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Solve the following equation using the quadratic formula. \( x^{2}+13 x+7=0 \) The solution set is \( \{ \) \}. (Simplify your answer, including any radicals and \( i \) as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)

Ask by Wade Goodwin. in the United States
Dec 18,2024

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Tutor-Verified Answer

Answer

\( x_{1}=-\frac{13+\sqrt{141}}{2}, x_{2}=\frac{-13+\sqrt{141}}{2} \)

Solution

Solve the equation \( x^{2}+13x+7=0 \). Solve the quadratic equation by following steps: - step0: Solve using the quadratic formula: \(x^{2}+13x+7=0\) - step1: Solve using the quadratic formula: \(x=\frac{-13\pm \sqrt{13^{2}-4\times 7}}{2}\) - step2: Simplify the expression: \(x=\frac{-13\pm \sqrt{141}}{2}\) - step3: Separate into possible cases: \(\begin{align}&x=\frac{-13+\sqrt{141}}{2}\\&x=\frac{-13-\sqrt{141}}{2}\end{align}\) - step4: Rewrite the fraction: \(\begin{align}&x=\frac{-13+\sqrt{141}}{2}\\&x=-\frac{13+\sqrt{141}}{2}\end{align}\) - step5: Rewrite: \(x_{1}=-\frac{13+\sqrt{141}}{2},x_{2}=\frac{-13+\sqrt{141}}{2}\) The solutions to the equation \(x^{2}+13x+7=0\) using the quadratic formula are \(x_{1}=-\frac{13+\sqrt{141}}{2}\) and \(x_{2}=\frac{-13+\sqrt{141}}{2}\).

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To solve the equation \( x^{2}+13 x+7=0 \) using the quadratic formula, we start with the formula itself: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] In this case, \( a = 1 \), \( b = 13 \), and \( c = 7 \). First, we calculate the discriminant: \[ b^2 - 4ac = 13^2 - 4 \cdot 1 \cdot 7 = 169 - 28 = 141 \] Now we substitute into the quadratic formula: \[ x = \frac{-13 \pm \sqrt{141}}{2 \cdot 1} = \frac{-13 \pm \sqrt{141}}{2} \] Thus, the solution set is \[ \left\{ \frac{-13 + \sqrt{141}}{2}, \frac{-13 - \sqrt{141}}{2} \right\} \]

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