Question
Solve the following equation using the quadratic formula. \( x^{2}+13 x+7=0 \) The solution set is \( \{ \) \}. (Simplify your answer, including any radicals and \( i \) as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)
Ask by Wade Goodwin. in the United States
Dec 18,2024
Real Tutor Solution
Tutor-Verified Answer
Answer
\( x_{1}=-\frac{13+\sqrt{141}}{2}, x_{2}=\frac{-13+\sqrt{141}}{2} \)
Solution
Solve the equation \( x^{2}+13x+7=0 \).
Solve the quadratic equation by following steps:
- step0: Solve using the quadratic formula:
\(x^{2}+13x+7=0\)
- step1: Solve using the quadratic formula:
\(x=\frac{-13\pm \sqrt{13^{2}-4\times 7}}{2}\)
- step2: Simplify the expression:
\(x=\frac{-13\pm \sqrt{141}}{2}\)
- step3: Separate into possible cases:
\(\begin{align}&x=\frac{-13+\sqrt{141}}{2}\\&x=\frac{-13-\sqrt{141}}{2}\end{align}\)
- step4: Rewrite the fraction:
\(\begin{align}&x=\frac{-13+\sqrt{141}}{2}\\&x=-\frac{13+\sqrt{141}}{2}\end{align}\)
- step5: Rewrite:
\(x_{1}=-\frac{13+\sqrt{141}}{2},x_{2}=\frac{-13+\sqrt{141}}{2}\)
The solutions to the equation \(x^{2}+13x+7=0\) using the quadratic formula are \(x_{1}=-\frac{13+\sqrt{141}}{2}\) and \(x_{2}=\frac{-13+\sqrt{141}}{2}\).
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Extra Insights
To solve the equation \( x^{2}+13 x+7=0 \) using the quadratic formula, we start with the formula itself: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] In this case, \( a = 1 \), \( b = 13 \), and \( c = 7 \). First, we calculate the discriminant: \[ b^2 - 4ac = 13^2 - 4 \cdot 1 \cdot 7 = 169 - 28 = 141 \] Now we substitute into the quadratic formula: \[ x = \frac{-13 \pm \sqrt{141}}{2 \cdot 1} = \frac{-13 \pm \sqrt{141}}{2} \] Thus, the solution set is \[ \left\{ \frac{-13 + \sqrt{141}}{2}, \frac{-13 - \sqrt{141}}{2} \right\} \]