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1) Determine the equation of the carcle a) Write down the value radus 5 3) Determine the gradient of the radus 5

Ask by Griffin Wheeler. in South Africa
Feb 04,2025

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The equation of the circle is \(x^2 + y^2 = 25\), the radius is 5, and the gradient of the radius at any point on the circle is \(-\cot(\theta)\).

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The equation of a circle can be expressed as \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius. Given a radius of 5, if we consider the center of the circle to be at the origin \((0, 0)\), the equation simplifies to \(x^2 + y^2 = 25\). The gradient of a radius of the circle can be understood as the slope of the line connecting the center to a point on the circle. If you take a point on the circle, such as \((5, 0)\), the gradient is calculated by finding the rise over run. Since the center is at the origin, the gradient from \((0, 0)\) to \((5, 0)\) would be \(0\), indicating a horizontal radius. For other points, you can apply the formula \(\text{slope} = \frac{y_2 - y_1}{x_2 - x_1}\).

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