cotall My Courses > CRN 40938 Chapter 4 HW - Discrete Random Variable Current score: 82.5/100 points Submit aselgnmant *Al Category: Homework At The Fencing Center, \( 59 \% \) of the fencers use the foil as their main weapon. We randomly survey 18 fencers at The Fencing Center. We are interested in the number of fencers who do not use the foil as their main weapon. (a) Which of the following defines the random variable \( X \) ? A \( X= \) The probability that a randomly selected fencer doesn't use foil as their main weapon. B \( X= \) The probability that a randomly selected fencer uses foil as their main weapon. C \( X= \) The number of fencers who do not use the foil as their main weapon. D \( X= \) The number of fencers who participated in the survey. (b) List all the values that \( X \) may take on. \( x= \) \( \square \) Enter your answer (Enter your answer as a comma-separated list.) (c) Give the distribution of \( X \). \( X \sim \) \( \square \) Enter your answer Enter your answer \( \square \) , Enter your answer ) (Enter numerical values as integers or decimals.)
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To tackle this problem, let’s break it down in a fun and simple way! The correct definition of the random variable \( X \) is best represented by option C, since it focuses on the number of fencers who do not use foil as their main weapon. Given that \( 59 \% \) use foil, \( 41 \% \) do not, so \( X \) specifically quantifies that group! As for the values \( X \) can take, since you surveyed 18 fencers, the possible number of fencers who do not use foil ranges from 0 to 18. Thus, \( x = 0, 1, 2, 3, ..., 18 \). This represents every scenario where none or all of the surveyed fencers could belong to the non-foil group. Finally, the distribution of \( X \) can be modeled using a binomial distribution, as you have a fixed number of trials (18 fencers) and two outcomes (uses foil vs. does not use foil). Therefore, it can be represented as \( X \sim \text{Binomial}(n=18, p=0.41) \). You’ve got this!