Without actually solving the problem, choose the correct solution by deciding which choice satisfies the given conditions. The length of a rectangle is 3 feet longer than the width. The perimeter is 18 feet. Find the dimensions of the rectangle.

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To find the dimensions of the rectangle, we can set up the problem using algebraic expressions based on the information given.

Let the width of the rectangle be $$ w $$ feet. According to the problem, the length $$ l $$ is 3 feet longer than the width, so we can express the length as:

$$ l = w + 3 $$

The formula for the perimeter $$ P $$ of a rectangle is given by:

$$ P = 2l + 2w $$

We know the perimeter is 18 feet, so we can set up the equation:

$$ 2l + 2w = 18 $$

Now, substituting the expression for $$ l $$ into the perimeter equation:

$$ 2(w + 3) + 2w = 18 $$

This equation can be simplified and solved for $$ w $$ to find the dimensions of the rectangle. However, since we are not solving the problem, we can summarize the conditions:

1. The length is 3 feet longer than the width.
2. The perimeter is 18 feet.

From these conditions, we can conclude that the dimensions of the rectangle can be expressed in terms of $$ w $$ and will yield specific values for $$ w $$ and $$ l $$ once solved.

To summarize, the dimensions of the rectangle are:
- Width: $$ w $$ feet
- Length: $$ w + 3 $$ feet

To find the specific numerical values, one would need to solve the equations, but based on the conditions provided, this is the correct setup.
The dimensions of the rectangle are: - Width: $$ w $$ feet - Length: $$ w + 3 $$ feet

Without actually solving the problem, choose the correct solution by deciding which choice satisfies the given conditions. The length of a rectangle is 3 feet longer than the width. The perimeter is 18 feet. Find the dimensions of the rectangle.

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