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If \( f(x)=2 x-1 \) and \( g(x)=3 x \) find \( f(g(3 a) \) 18a-1 \( \begin{array}{l}-18 a-1 \\ 18 x-1 \\ -18 x-1\end{array} \)

Ask by Mcdonald Peters. in the Philippines
Dec 07,2024

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\( f(g(3a)) = 18a - 1 \)

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Beyond the Answer

To find \( f(g(3a)) \), we start by calculating \( g(3a) \). Given \( g(x) = 3x \), we have: \[ g(3a) = 3(3a) = 9a \] Next, we substitute \( g(3a) \) into \( f(x) \). Given \( f(x) = 2x - 1 \): \[ f(g(3a)) = f(9a) = 2(9a) - 1 = 18a - 1 \] So the correct answer is \( 18a - 1 \).

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