Each of the base angles of the isosceles triangle is

It looks like your question got cut off. However, I can provide some general information about the base angles of an **isosceles triangle**: ### **Properties of an Isosceles Triangle:** 1. **Two Equal Sides:** An isosceles triangle has at least two sides that are equal in length. 2. **Two Equal Base Angles:** The angles opposite the equal sides are also equal. These are referred to as the **base angles**. 3. **Vertex Angle:** The angle formed by the two equal sides is called the **vertex angle**. ### **Calculating Base Angles:** The sum of all interior angles in any triangle is **180 degrees**. In an isosceles triangle: - Let’s denote each base angle as \( x \) degrees. - If the vertex angle is \( y \) degrees, then: \[ x + x + y = 180 \\ 2x + y = 180 \\ 2x = 180 - y \\ x = \frac{180 - y}{2} \] - **Example:** If the vertex angle (\( y \)) is \( 40^\circ \): \[ x = \frac{180 - 40}{2} = \frac{140}{2} = 70^\circ \] So, each base angle is \( 70^\circ \). ### **Special Case – Isosceles Triangle with Two Equal Angles:** If you know that the two base angles are equal and want to find their measure without knowing the vertex angle, you might need additional information, such as the length of the sides or another angle. ### **Further Assistance:** If you have a specific problem or additional information regarding the isosceles triangle you're working with, feel free to share it! I'd be happy to help you solve it.