Two times a number plus three times another equals 13. The sum of the two numbers is 7. What are the numbers?
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Let's consider the problem! We have two unknowns, so let's call them \( x \) and \( y \). From the first equation, we know that \( 2x + 3y = 13 \), and from the second equation, we have \( x + y = 7 \). To solve this, we can express \( y \) in terms of \( x \) using the second equation: \( y = 7 - x \). Now, substitute \( y \) in the first equation: \[ 2x + 3(7 - x) = 13 \] Distributing gives us: \[ 2x + 21 - 3x = 13 \] Combining like terms results in: \[ -x + 21 = 13 \] Now, solving for \( x \): \[ -x = 13 - 21 \] \[ -x = -8 \] \[ x = 8 \] Now that we have \( x \), we can find \( y \): \[ y = 7 - 8 = -1 \] Thus, the two numbers are \( x = 8 \) and \( y = -1 \). So there you go, math magic!