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Home Question Bank Math Pre Calculus Archive 2024 November 09

Pre-calculus Questions from Nov 09,2024

Browse the Pre-calculus Q&A Archive for Nov 09,2024, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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'ensemble de définition de la fonction \( f(x)=\frac{1}{x^{2}-2 x-3} \) est \[ -\infty, a \backslash \cup \mid a, b[\cup \mid b,+\infty[ \] L'ensemble de définition de la fonction \( x \mapsto-\frac{1}{1-x} \) est Problem 7. (1 point) The amount in grams of a drug in the body \( t \) hours after latring a pill is given by \( A(t)=18(0.85)^{t} \). (a) What is the initial dose given? (b) What percent of the drug leaves the body after each hour? (c) What is the amount of drug left after 11 hours? Note: You can earn partial credit on this problem. \( f(x)=(x-3)^{2}+8 \) \#7: Find all of the characteristics of the function \& graph. \#6: Find all of the characteristics of the function \& graph. \[ f(x)=-1 / 3(x+2)^{2}+1 \] Es la equivalencia en grados de \( \frac{3}{5} \pi \) Dada la función \( f: R \rightarrow R \) tal que \( f(x)=y=\frac{x^{2}+1}{2} \), hacer su representación gráfica indicando el dominio, el rango o recorrido y que clase de función es. Finding a final amount in a word problem on exponential growth or decay The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 140 grams of a rades the calculator provided and round your answer to the nearest gram. Finding a final amount in a word problem on exponential growth or decay A certain forest covers an area of \( 3500 \mathrm{~km}^{2} \). Suppose that each year this area decreases by \( 7.25 \% \). What will the area be after 14 years Use the calculator provided and round your answer to the nearest square kilometer. 7) Para calcular la superficie de un cuerpo a (en metros cuadrados), dado el peso m de una persona (en kilogramos) y su altura n (en centímetros), los investigadores médicos utilizan la fórmula empírica: \[ \log a=-2,144+(0,145) \log \mathrm{m}+(0,725) \log \mathrm{n} \] A. Es \( 0,56 \mathrm{~m}^{2} \). B. Es es é área aproximada del cuerpo de un hombre cuyo peso es de 70 kg y su altura \( 1,75 \mathrm{~m} \) ? C. Es \( 0,056 \mathrm{~m}^{2} \). D. Es \( 0,506 \mathrm{~m}^{2} \).
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