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Home Question Bank Physics Archive 2025 January 22

Physics Questions from Jan 22,2025

Browse the Physics Q&A Archive for Jan 22,2025, featuring a collection of homework questions and answers from this day. Find detailed solutions to enhance your understanding.

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9 Un téléviseur, de puissance 150 W , a consommé \( 0,9 \mathrm{~Wh} \) pendant une durée t . Calculer t . a. If \( \vec{A}=(4) \hat{i}+(-4) \hat{j}+(5) \hat{k} \), and \( \vec{B}=(8) \hat{i}+(3) \hat{j}+(5) \hat{k} \), the x-component of \( \vec{S}=\vec{A}+\vec{B} \) is then b. the z-component of \( \vec{S} \) is then 10 c. If \( \vec{A}=(4) \hat{i}+(-4) \hat{j}+(5) \hat{k} \), and \( \vec{B}=(8) \hat{i}+(3) \hat{j}+(5) \hat{k} \), the x-component of \( \vec{D}=\vec{A}-\vec{B} \) is then -4 d. the y-component of \( \vec{D} \) is then -7 e. \( \vec{B} \cdot \vec{A}= \) \[ \vec{A} \cdot \vec{B} \] \( \quad-\vec{A} \cdot \vec{B} \) a. If \( \vec{A}=(4) \hat{i}+(-4) \hat{j}+(5) \hat{k} \), and \( \vec{B}=(8) \hat{i}+(3) \hat{j}+(5) \hat{k} \), the x-component of \( \vec{S}=\vec{A}+\vec{B} \) is then b. the z-component of \( \vec{S} \) is then c. If \( \vec{A}=(4) \hat{i}+(-4) \hat{j}+(5) \hat{k} \), and \( \vec{B}=(8) \hat{i}+(3) \hat{j}+(5) \hat{k} \), the x-component of \( \vec{D}=\vec{A}-\vec{B} \) is then d. the y-component of \( \vec{D} \) is then e. \( \vec{B} \cdot \vec{A}= \) \( \quad \vec{A} \cdot \vec{B} \) \( \quad-\vec{A} \cdot \vec{B} \) Fo to the University of Colorado Boulder website and select the "Wave Interference" simulation (https://phet.colorado.edu/en/simulation/wave-interference). You can activate it right in the window by clicking on it. You can also download to your computer if you wish. 1. Select the 'Slits' mode. The wave generator here sends out water waves when the green button is pushed. With the one slit in the barrier, set its width to 0.5 cm . Start sending out waves. What happens to the waves as they pass the barrier? 2. Change the units of the following speeds as indicated: (a) \( 72 \mathrm{~km} / \mathrm{h} \) into \( \mathrm{m} / \mathrm{s} \) । (b) \( 108 \mathrm{~km} / \mathrm{h} \) into \( \mathrm{m} / \mathrm{s} \) (c) \( 300 \mathrm{~km} / \mathrm{h} \) into \( \mathrm{m} / \mathrm{s} \) (d) \( 30 \mathrm{~m} / \mathrm{s} \) into \( \mathrm{km} / \mathrm{h} \mathrm{x} \) (e) \( 22 \mathrm{~m} / \mathrm{s} \) into \( \mathrm{km} / \mathrm{h} \) (f) \( 0.012 \mathrm{~m} / \mathrm{s} \) into \( \mathrm{cm} / \mathrm{s} \mathrm{x} \cdot 00 \) (g) \( 9000 \mathrm{~cm} / \mathrm{s} \) into \( \mathrm{m} / \mathrm{s} \) (h) \( 600 \mathrm{miles} / \) day into miles per hour (i) \( 2592 \mathrm{miles} / \) day into miles per second 10. With frequency at max value look at the string, Is it a standing wave? How do youknour? (hint: look at the string at 7 cm on the ruler, Is the string there alternating or always one part of a wave? For a given circuit, \( \mathrm{L}=3 \mathrm{mH}, \mathrm{R}=0, \mathrm{C}=50 \mathrm{nF} \), and \( \mathrm{E}=0 \). Find the equation relating the charge and the time if \( \mathrm{q}=10^{5} \mathrm{C} \) and \( \mathrm{i}=0 \) when \( \mathrm{t}=0 \). Choose the correct equation below. A. \( q=\cos 81,650 \mathrm{t} \) B. \( q=100,000 \sin 81,650 \mathrm{t} \) C. \( q=100,000 \cos 81,650 \mathrm{t} \) D. \( q=100,000 \cos 0.0816 \mathrm{t} \) 8. Find the frequencies for the \( 2^{\text {nd }} \) and \( 3^{\text {rd }} \) harmonics. (keep in mind the note from the previous problem) 6. Set amplitude to 0.70 cm . Set damping to 'none.' Watch the wave go for several seconds. How does it change? Is there a cycle to it? Why does this happen (Hint: think about beats)? text Calibri 11 B \( I \) \( \underline{U} \) A \( \leftrightarrow \) Swap to "oscillate" (top left). What affect does changing the amplitude have on the wave? Hov do you think amplitude relates to energy?
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