If \( \mathrm{m} \angle A=x^{2}-6 x, \mathrm{~m} \angle B=2 x-3 \), and \( \mathrm{m} \angle A C D=9 x+27 \), what is the value of \( x \) ? 1) 10 2) 2 3) 3 4) 15 8 In rhombus \( A B C D \), the diagonals \( \overline{A C} \) and \( \overline{B D} \) intersect at \( E \). If \( A E=5 \) and \( B E=12 \), what is the length of \( \overline{A B} \) ? 1) 7 2) 10 3) 13 4) 17 9calene triangle \( A B C \) is similar to triangle \( D E F \). Which statement is false? 1) \( A B: B C=D E: E F \) 2) \( A C: D F=B C: E F \) 3) \( \angle A C B \cong \angle D F E \) 4) \( \angle A B C \cong \angle E D F \)
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Mind Expander
To solve for \(x\), we know that in any triangle, the measures of angles should sum up to 180 degrees. Setting up the equation: \[ x^2 - 6x + (2x - 3) + (9x + 27) = 180 \] This simplifies to: \[ x^2 + 5x + 24 = 180 \quad \Rightarrow \quad x^2 + 5x - 156 = 0 \] Using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), we can solve for \(x\). Thus, the possible solutions need to be checked against provided options. --- In rhombus \(ABCD\), the diagonals intersect at right angles and bisect each other. To find the length of \(AB\): Using the Pythagorean theorem, we calculate \(AB\): \[ AB = \sqrt{AE^2 + BE^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \] Thus, the length of \(\overline{AB}\) is indeed 13, confirming that option 3 is correct.